x^2+2011x+2010=0

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Solution for x^2+2011x+2010=0 equation:



x^2+2011x+2010=0
a = 1; b = 2011; c = +2010;
Δ = b2-4ac
Δ = 20112-4·1·2010
Δ = 4036081
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4036081}=2009$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2011)-2009}{2*1}=\frac{-4020}{2} =-2010 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2011)+2009}{2*1}=\frac{-2}{2} =-1 $

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