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x^2+2011x+2010=0
a = 1; b = 2011; c = +2010;
Δ = b2-4ac
Δ = 20112-4·1·2010
Δ = 4036081
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4036081}=2009$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2011)-2009}{2*1}=\frac{-4020}{2} =-2010 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2011)+2009}{2*1}=\frac{-2}{2} =-1 $
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